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Nový pohled na Titius-Bodeho řadu
3848 otázku odeslal(a) Jiří v Neděli 8.Října 2006 09:34:49
http://www.kolumbus.fi/tilmari/titius.htm
Timo Niroma: Titius-Bode of my own
I have wondered since the 1970's, when I discovered the following law, which is inspired by the Titius-Bode law, works. Nevertheless:
First I divided the planets into three groups so that each group consisted of three planets. Then there were the leftovers, that remained as a loose group, the so called Kuiper belt. The groups were:
1. The small planets that were born from the heavy debris that remained near the Sun:
Mercury, Venus and the double planet Earth/Moon.
2. Then the main ring consisting of dirty gas, meaning gas with still some heavy elements:
Mars, debris with too small amount of dust to coalesce and small sister of sun, Jupiter. Solar wind seems to have swept the light elements to the end of this ring.
3. The ring of relatively light gas, from which were born
Saturn, Uranus and Neptune.
The three rings (plus possibly the Kuiper belt) adjusted to their places avoiding arithmetic resonance, but remaining in a geometric resonance to each other.
This also happened inside the rings, when gravity began to coalesce the material into three rings, which with one exception then coalesced into planets. The resonance placed the planets into the low and high end of the ring plus into the geometrical, not arithmetical center of it.
What is amazing, is that it seems that the same resonance law that placed the planets into their positions, reigns also in the nucleus of the atom, where the average amount of neutrons seems to make the atomic weight (the average of the reigning isotopes) behave in equal ways as the resonance of planets. What happens in small scale seems to obey the same laws on a much grander scale.
Before I introduce my equation, I remark that actually it needs a factor, let's call it k, with which the atomic weights should be multiplied. But when we use kilometers as the distance measure of planets, it is so near to 1, that for clarity's sake I have omitted it. When using some non-SI measure stick, such as miles, you need it.
Then let's begin with the first planets. Their distance corresponds to atomic weight of the element number 2.5*n, where n is the number of planet from the sun. When the atomic weight is multiplied by (k*) tens of millions of kilometers, we get the distance of the planet.
Mercury 58 mill.km / 2=helium, 3=litium --> (4+6.94)/2= 5.5 / 106%
Venus 108 mill.km / 5 = borium --> 10.8 / 100%
Earth 150 mill.km / 7=nitrogen, 8=oxygen --> (14+16)/2=15.0 / 100%
Now the gap between the two first rings means that we must add 3.5 elements (1 for the preceding group and 2.5 for the distance of the group) so that Mars does not correspond to element 10 but 11, and the next series goes 11*n, where Mars gets the number one, asteroids 2 and Jupiter 3.
Mars 228 mill. km / 11 = sodium --> 23.0 / 99%
asteroids 472 mill. km *) / 22 = titanium --> 47.9 / 99%
Jupiter 778 mili. km / 33 = arsenium --> 74.9 / 104%
*) Calculated from the densest group avg. (Binzel-Gehrels-Matthews, Arizona, 1989)
Now to the third group. Albeit the elements are ending just before Uranus, but let's try. Now we need to add for the gap 26.5 elements (2 for the groups, and 2.5 and 2*11 for the distances of the groups), so that Saturn equals element 59.5 instead of 44 (2+2.5+11). The series goes then 59.5*n, where Saturn is 1, Uranus 2 and Neptune 3.
Saturn 1427 mil.km / 59=praseodyme, 60=neodyme --> (140.91+144.24)/2=142.6 / 100%
Uranus 2871 mil.km / 119 --> 295 *)
/ 97%
Neptune 4497 mil.km / 178.5 --> c. 460 **)
/c.98%
*) extrapolated from elements 116 and 118 **) estimate based on the known part of the element table
Questions arise, how and why. The fit is however so good, that it somehow cries for an explanation. And without it, it would give some hints, how our solar system got started. And also how the average number of neutrons in atoms get their number.
Comments should be addressed to timo.niroma@pp.inet.fi